📐 Class 10 Mathematics — Coordinate Geometry Interactive Visual Revision Notes Aligned with the Class 10 Mathematics syllabus. Independently created study material. Not affiliated with or endorsed by NCERT.

📋 What is Inside?

📝 Section 1 — Classroom Notes

📐 Topic 1: What Is Coordinate Geometry?

🌎 Real World Connection: The GPS in your phone uses coordinate geometry — every location on Earth is described by a latitude (y) and longitude (x). Delivery apps calculate the shortest route between two (x, y) addresses. Video games place every character, wall, and bullet using (x, y) positions. Even the pin you drop on a map is just a point with two coordinates.

📐 Topic 2: The Cartesian Plane

📐 Topic 3: Quadrants

📐 Topic 4: Distance Formula

📐 Topic 5: Steps to Find Distance

📐 Topic 6: Section Formula

📐 Topic 7: Mid-Point Formula

📐 Topic 8: Area of a Triangle

📐 Topic 9: Collinearity of Points

📐 Topic 10: Centroid of a Triangle

🎨 Section 2 — Easy Illustrations

The Four Quadrants X Y O Quadrant I (+, +) Quadrant II (−, +) Quadrant III (−, −) Quadrant IV (+, −) (3, 4) (−5, 4) (−5, −3) (3, −3)

Picture 1 — The four quadrants with one point in each

Distance Formula — Right Triangle (8, 5) A(2, 5) B(8, 13) 8 − 2 = 6 13 − 5 = 8 d = √(36 + 64) = √100 = 10 Horizontal gap Vertical gap Distance

Picture 2 — Distance = hypotenuse of a right triangle

Section Formula — Dividing a Segment A(x₁, y₁) B(x₂, y₂) P m n P = ( (mx₂+nx₁)/(m+n) , (my₂+ny₁)/(m+n) )

Picture 3 — Point P divides AB in ratio m : n

Mid-Point — Average the Coordinates A(3, 1) B(9, 7) M x = (3+9) ÷ 2 = 6 y = (1+7) ÷ 2 = 4 Mid-point M = (6, 4)

Picture 4 — Just average the x and y values

Area of a Triangle from Coordinates A(1, 2) B(4, 6) C(7, 2) 1 4 7 2 6 Area = 12 square units

Picture 5 — Plot the three vertices and use the formula

✏️ Section 3 — Worked Examples

✏️ Example 1: Distance Between Two Points

Find the distance between (2, 5) and (8, 13).

1 Formula: d = √[(x₂−x₁)² + (y₂−y₁)²]
2 Put values: d = √[(8−2)² + (13−5)²]
3 Simplify: d = √[(6)² + (8)²]
4 Calculate: d = √[36 + 64] = √100
5 d = 10 units
🎯 Distance = 10 units

✏️ Example 2: Section Formula

Find the point dividing (1, 3) and (7, 9) in ratio 2:1.

1 Here m = 2, n = 1
2 x = (2×7 + 1×1) ÷ (2+1) = 15 ÷ 3 = 5
3 y = (2×9 + 1×3) ÷ (2+1) = 21 ÷ 3 = 7
🎯 The point is (5, 7)

✏️ Example 3: Area of a Triangle

Find area with vertices (1, 2), (4, 6), (7, 2).

1 Formula: ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|
2 Put values: ½|1(6−2) + 4(2−2) + 7(2−6)|
3 Simplify: ½|4 + 0 + (−28)|
4 Calculate: ½|−24| = ½ × 24
5 Area = 12 square units
🎯 Area = 12 square units

📊 Section 4 — Cheat Sheet

ConceptFormulaKey Point
Distance√[(x₂−x₁)²+(y₂−y₁)²]Always positive or zero
Section Formula((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n))m : n is the ratio
Mid-Point((x₁+x₂)/2, (y₁+y₂)/2)Special case: ratio 1:1
Area of Triangle½|x₁(y₂−y₃)+x₂(y₃−y₁)+x₃(y₁−y₂)|Use absolute value
CollinearityArea = 0Points on one line
Centroid((x₁+x₂+x₃)/3, (y₁+y₂+y₃)/3)Where medians meet

📄 Section 5 — Take-Home Handout

Part 1: Key Words to Remember

Write your own definitions here ...

Part 2: Quick Formula List

Write the formulas from memory ...

Part 3: Practice Problems

Show your working here ...

Part 4: Common Mistakes

Note which mistakes you make ...

Part 5: Real-Life Uses

Can you think of more examples?

✅ Detailed Solutions

Part 3: Practice Problems — Full Working

1. Find distance from (0, 0) to (5, 12):

1 Formula: d = √[(x₂−x₁)² + (y₂−y₁)²]
2 d = √[(5−0)² + (12−0)²] = √[25 + 144] = √169
3 √169 = 13 units
Distance from (0,0) to (5,12) = 13 units

2. Find mid-point of (6, 2) and (10, 8):

1 x = (x₁ + x₂)/2 = (6 + 10)/2 = 16/2 = 8
2 y = (y₁ + y₂)/2 = (2 + 8)/2 = 10/2 = 5
Mid-point M = (8, 5)

3. Is area zero for (1,1), (3,3), (5,5)?

1 Area = ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|
2 = ½|1(3−5) + 3(5−1) + 5(1−3)|
3 = ½|1(−2) + 3(4) + 5(−2)| = ½|−2 + 12 − 10| = ½ × 0 = 0
4 Area = 0 → Points are collinear (they all lie on the line y = x).
Area = 0; Points (1,1), (3,3), (5,5) are collinear

🃏 Section 6 — Revision Flashcards

📍 What are coordinates?
A pair (x, y) showing a point's position on a plane.
📈 What is the origin?
The point (0, 0) where both axes cross.
📏 How many quadrants exist?
Four: I (+,+), II (−,+), III (−,−), IV (+,−).
📏 What does distance formula find?
The straight-line length between two points.
✂ What is section formula for?
To find a point that splits a segment in ratio m:n.
💡 How do you find a mid-point?
Average the x-values and average the y-values.
🔶 When are three points collinear?
When the triangle area they form equals zero.
🎯 What is the centroid?
Where all three medians meet. Average all vertices.

🧠 Section 7 — Mind Map

Coordinate Geometry Cartesian Plane x-axis & y-axis Origin (0, 0) Quadrants I, II, III, IV Distance Formula Pythagoras based Section Formula Ratio m : n Mid-Point Average of ends Area of Triangle ½ |determinant| Centroid Medians meet

Hover on any branch to focus it. All key ideas connected together.