⭕ Maths Class 9 NCERT Lesson 5 Circles Special Edition for Easy Learning

What is inside?

📝 Section 1 — Classroom Notes

🌎 Real-World Hook: Look at a bicycle wheel, a clock face, a coin, or the pupils of your eyes — they are all circles! A circle is the most perfect shape in nature. Planets orbit in paths close to circles. A dartboard has rings that are circles. Even a pizza is circular! Whenever engineers design wheels, pipes, or domes, they use the properties of circles. In this lesson, you will discover the beautiful mathematical rules that govern this perfect shape.

Topic 1: What is a Circle?

Topic 2: Symmetry of a Circle

Topic 3: Circles Through Points

Topic 4: Circumcircle of a Triangle

Topic 5: Equal Chords and Angles

Topic 6: Centre to Chord is 90°

Topic 7: Equal Chords = Same Distance

Topic 8: Major Arc and Minor Arc

Topic 9: Angle at Centre = 2 × Angle on Circle

Angle at centre = 2 × Angle on circle

Topic 10: Cyclic Quadrilateral

Opposite angles of cyclic quadrilateral = 180°

🎨 Section 2 — Illustrations

Picture 1: Parts of a Circle

Parts of a Circle Centre (O) Radius (r) Diameter (d = 2r) Chord Minor Arc Major Arc Diameter is the longest chord. It passes through the centre.

A circle showing centre, radius, diameter, chord, and arcs.

Picture 2: Circumcircle of a Triangle

Circumcircle of a Triangle A B C O (circumcentre) Perpendicular bisectors of sides meet at the circumcentre O.

One unique circle passes through all 3 corners of a triangle.

Picture 3: Centre to Chord = 90°

Centre to Midpoint of Chord = 90° C A B M (midpoint) 90° AM = BM The line from centre to midpoint of chord is always perpendicular.

CM is perpendicular to chord AB. It also bisects the chord.

Picture 4: Angle at Centre = 2 × Angle on Circle

Angle at Centre = 2 × Angle on Circle O A B D 2x x Centre angle (2x) is always double the circle angle (x)

Arc AB makes angle 2x at centre O and angle x at point D on the circle.

Picture 5: Cyclic Quadrilateral

Cyclic Quadrilateral: Opposite Angles = 180° A B C D a b c d a + c = 180° b + d = 180°

In a cyclic quadrilateral, opposite angles always add up to 180°.

📐 Section 3 — Worked Examples

Example 1: Find the Chord Length

A circle has radius 13 cm.

The chord is 5 cm away from the centre.

Find the length of the chord.

1 Draw the picture. Centre C, chord AB, midpoint M.
2 CM = 5 cm (distance to chord).
3 CA = 13 cm (radius).
4 Triangle CMA has a 90° angle at M.
5 Use Pythagoras: AM² = CA² − CM²
6 AM² = 13² − 5² = 169 − 25 = 144
7 AM = √144 = 12 cm
8 AB = 2 × AM = 2 × 12 = 24 cm
Chord length = 24 cm

Formula used: AM² + CM² = radius²

Example 2: Find the Angle on the Circle

An arc makes a 70° angle at the centre.

What angle does it make at a point on the circle?

1 The rule: centre angle = 2 × circle angle.
2 Centre angle = 70°
3 Circle angle = 70° ÷ 2 = 35°
Angle on circle = 35°

Rule: Centre angle = 2 × circle angle

Example 3: Is it a Cyclic Quadrilateral?

A quadrilateral has angles: 80°, 100°, 100°, 80°.

Is it cyclic?

1 Check: do opposite angles add to 180°?
2 Pair 1: 80° + 100° = 180° ✔
3 Pair 2: 100° + 80° = 180° ✔
4 Both pairs add to 180°. Yes, it is cyclic!
Yes, it is a cyclic quadrilateral.

Rule: Opposite angles must add to 180°

📋 Section 4 — Cheat Sheet

Word / RuleWhat It Means
CircleAll points same distance from centre
RadiusDistance from centre to circle
DiameterLongest chord. Passes through centre. d = 2r
ChordA line joining two points on the circle
ArcA curved part of the circle
CircumcircleCircle through all 3 corners of a triangle
CircumcentreCentre of circumcircle. Where bisectors meet
Equal chordsMake equal angles at centre. Same distance from centre
Centre to chordLine from centre to midpoint is 90° to chord
Centre angle ruleCentre angle = 2 × angle on circle
Angle in semicircleAlways 90°
Cyclic quadrilateralAll 4 corners on one circle. Opposite angles = 180°

✏️ Section 5 — Handout

A. Fill in the Blanks

1. The distance from centre to circle is ________.

2. Diameter = 2 × ________.

3. The longest chord of a circle is the ________.

4. Through 3 non-collinear points, there is ________ circle.

5. Centre angle is ________ times the circle angle.

B. True or False

1. A circle has only 4 lines of symmetry. ________

2. Equal chords make equal angles at centre. ________

3. Angle in a semicircle is 90°. ________

4. The diameter is the shortest chord. ________

C. Solve

1. Radius = 10 cm. Distance to chord = 6 cm.

Find the chord length.

Show your work here

2. Centre angle = 120°. Find the angle on the circle.

Show your work here

D. Match the Columns

1. Circumcentre — (a) Longest chord

2. Diameter — (b) Opposite angles = 180°

3. Cyclic quadrilateral — (c) Where bisectors meet

4. Radius — (d) Centre to circle distance

E. Draw and Label

Draw a circle. Mark and label:

Centre, Radius, Diameter, Chord, Arc.

Draw your circle here

✅ Detailed Solutions — Handout Practice

✓ A. Fill in the Blanks — Answers

1 The distance from centre to circle is radius.
2 Diameter = 2 × radius.
3 The longest chord of a circle is the diameter.
4 Through 3 non-collinear points, there is exactly one circle.
5 Centre angle is twice (2 times) the circle angle (inscribed angle theorem).
🏆 Answers: (1) radius   (2) radius   (3) diameter   (4) exactly one   (5) twice

✓ B. True or False — Answers

1 "A circle has only 4 lines of symmetry." → FALSE. A circle has infinite lines of symmetry (every diameter is a line of symmetry).
2 "Equal chords make equal angles at centre." → TRUE. This is a standard circle theorem.
3 "Angle in a semicircle is 90°." → TRUE. This is Thales' theorem — an angle inscribed in a semicircle is always a right angle.
4 "The diameter is the shortest chord." → FALSE. The diameter is the longest chord (it passes through the centre).
🏆 Answers: (1) False   (2) True   (3) True   (4) False

✓ C. Problem 1: Radius = 10 cm, Distance to chord = 6 cm. Find chord length.

1 Draw the picture: The perpendicular from the centre (O) to the chord (AB) bisects the chord. Call the midpoint M.
2 Label: OA = radius = 10 cm. OM = distance from centre to chord = 6 cm.
3 Triangle OMA is right-angled at M. Use Pythagoras: AM² = OA² − OM².
4 AM² = 10² − 6² = 100 − 36 = 64.
5 AM = √64 = 8 cm.
6 Since M bisects AB: chord AB = 2 × AM = 2 × 8 = 16 cm.
🏆 Answer: Chord length = 16 cm.

✓ C. Problem 2: Centre angle = 120°. Find the inscribed angle on the circle.

1 Recall the theorem: The angle at the centre = 2 × the angle at the circle (inscribed angle theorem).
2 So: inscribed angle = centre angle ÷ 2.
3 Inscribed angle = 120° ÷ 2 = 60°.
🏆 Answer: The angle on the circle = 60°.

🃏 Section 6 — Revision Flashcards

Front
What is a circle?
Back

All points that are the same distance from a centre point.

Front
What is the diameter?
Back

The longest chord. It passes through the centre. d = 2 × r.

Front
How many circles through 3 points (not in a line)?
Back

Exactly ONE circle. It is called the circumcircle.

Front
What does centre to midpoint of chord make?
Back

A 90° angle with the chord. It is perpendicular.

Front
Equal chords make what at the centre?
Back

Equal angles at the centre. Same length = same angle.

Front
Centre angle vs angle on circle?
Back

Centre angle = 2 × angle on circle. Double!

Front
Angle in a semicircle?
Back

Always 90°. Diameter makes 180° at centre, half = 90°.

Front
Opposite angles of a cyclic quadrilateral?
Back

They add up to 180°. Always!

🧠 Section 7 — Mind Map

CIRCLES Chapter 5 Definition All points same distance from centre = circle Parts Centre, Radius, Diameter Chord, Arc Symmetry Infinite lines of symmetry Full rotational symmetry Circumcircle 3 points = 1 circle Bisectors meet at centre Chord Rules Equal chords = equal angles Centre to midpoint = 90° Angle Rule Centre angle = 2 × circle angle Semicircle angle = 90° Arcs Major arc (big part) Minor arc (small part) Cyclic Quadrilateral 4 points on one circle Opposite angles = 180°

All the key ideas about circles in one picture.