🔢 Class 9 Mathematics — Sequences and Progressions Original Visual Revision Notes Aligned with the Class 9 Mathematics syllabus. Independently created study material. Not affiliated with or endorsed by NCERT.

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📝 Section 1 — Classroom Notes

🌎 Real-World Hook: Have you ever saved pocket money — ₹20 on day 1, ₹20 on day 2, and so on? By day 10 you have ₹200. That steady growth is an arithmetic progression! Or imagine bacteria that double every hour — 1, 2, 4, 8, 16 ... That explosive growth is a geometric progression! Sequences are everywhere: the stitches in knitting, the notes in a musical scale, the floors of a building, the pattern of stadium seats. Once you spot the rule, you can predict any term — even the 100th — without listing them all!

Topic 1: What is a Sequence?

Topic 2: Patterns in Sequences

Topic 3: Explicit Rule (nth Term)

Explicit rule: plug in n, get the term

Topic 4: Recursive Rule

Topic 5: Arithmetic Progression (AP)

Topic 6: Common Difference

Common difference: d = t(n) − t(n−1)

Topic 7: nth Term of an AP

t(n) = a + (n − 1) × d

Topic 8: Sum of First n Natural Numbers

Sum = n × (n + 1) ÷ 2

Topic 9: Geometric Progression (GP)

Topic 10: Common Ratio and nth Term of GP

t(n) = a × r(n−1)

🎨 Section 2 — Illustrations

Picture 1: Sequence Staircase

A Sequence is Like a Staircase 5 t(1) 9 t(2) 13 t(3) 17 t(4) 21 t(5) +4 +4 +4 +4 Rule: t(n) = 4n + 1   |   Add 4 each time

Each step is 4 higher than the last. That makes it an AP!

Picture 2: AP on a Number Line

AP on a Number Line (d = 6) 3 9 15 21 27 +6 +6 +6 +6 a = 3, d = 6   |   t(n) = 3 + (n−1) × 6 = 6n − 3

In an AP, the jumps between terms are always the same size.

Picture 3: GP Doubling

GP: Multiply by 2 Each Time Stage 1 3 Stage 2 6 Stage 3 12 Stage 4 24 24 ×2 ×2 ×2 GP: 3, 6, 12, 24, ...  |  a = 3, r = 2 t(n) = 3 × 2(n−1)

In a GP, each stage has double the dots. Growth is very fast!

Picture 4: AP vs GP Comparison

AP Grows Slowly. GP Grows Fast! Term number (n) Value 1 2 3 4 5 AP (add 5) GP (× 2)

AP grows by the same amount each time. GP grows by the same factor — much faster!

Picture 5: Sum of Natural Numbers

Sum of 1 + 2 + 3 + 4 = ? Pair up numbers from both ends! 1 2 3 4 4 3 2 1 5 5 = = Each pair adds to 5 4 pairs = n+1 2 × S = 4 × 5 = 20 S = 20 ÷ 2 = 10 Formula: S = n × (n + 1) ÷ 2 Works for any n! S(100) = 100 × 101 ÷ 2 = 5050

Write the sum forward and backward. Each pair adds to n+1. There are n pairs. Divide by 2.

📐 Section 3 — Worked Examples

Example 1: Find the 8th term of an AP

An AP has first term a = 5 and common difference d = 4.

Find the 8th term.

1 Write the formula: t(n) = a + (n − 1) × d.
2 Put in the values: t(8) = 5 + (8 − 1) × 4.
3 Simplify inside the bracket: 8 − 1 = 7.
4 Multiply: 7 × 4 = 28.
5 Add: 5 + 28 = 33.
t(8) = 33

t(n) = a + (n − 1) × d

Example 2: Sum of First 15 Natural Numbers

Find 1 + 2 + 3 + ... + 15.

1 Use the formula: S = n × (n + 1) ÷ 2.
2 Here n = 15.
3 S = 15 × (15 + 1) ÷ 2.
4 S = 15 × 16 ÷ 2.
5 S = 240 ÷ 2 = 120.
S = 120

S = n × (n + 1) ÷ 2

Example 3: Find the 7th Term of a GP

A GP has first term a = 3 and common ratio r = 2.

Find the 7th term.

1 Write the formula: t(n) = a × r(n−1).
2 Put in the values: t(7) = 3 × 2(7−1).
3 Simplify the power: 26 = 64.
4 Multiply: 3 × 64 = 192.
t(7) = 192

t(n) = a × r(n−1)

📋 Section 4 — Cheat Sheet

Word / RuleWhat It Means
SequenceAn ordered list of numbers (terms)
TermOne number in a sequence
Explicit ruleFormula that uses n to find any term
Recursive ruleUses the previous term to find the next
AP (Arithmetic Progression)Add the same number (d) each time
d (common difference)The fixed amount added in an AP
AP nth termt(n) = a + (n − 1) × d
Sum of 1 to nS = n × (n + 1) ÷ 2
GP (Geometric Progression)Multiply by the same number (r) each time
r (common ratio)The fixed multiplier in a GP
GP nth termt(n) = a × r(n−1)
Finite sequenceHas a last term (ends)
Infinite sequenceGoes on forever (no end)

✏️ Section 5 — Handout

A. Fill in the Blanks

1. A sequence is an ordered list of ________.

2. In an AP, we add the same number called the ________.

3. The nth term of an AP is t(n) = ________ + (n − 1) × ________.

4. In a GP, we multiply by the same number called the ________.

5. Sum of 1 to n = n × (n + 1) ÷ ________.

B. True or False

1. 2, 5, 8, 11, 14 is an AP with d = 3. ________

2. 1, 3, 9, 27 is an AP. ________

3. In a GP, you add the same number each time. ________

4. The sum of 1 to 10 is 55. ________

C. Solve

1. AP has a = 7, d = 3. Find the 10th term.

Show your work here

2. Find the sum of 1 + 2 + 3 + ... + 20.

Show your work here

D. Match the Columns

1. AP — (a) Multiply by same number

2. GP — (b) Add same number

3. Common difference — (c) n(n+1)/2

4. Sum of 1 to n — (d) The fixed amount added

E. Write the Next 3 Terms

1. AP: 4, 9, 14, __, __, __

2. GP: 5, 10, 20, __, __, __

Write your answers here

✅ Detailed Solutions — Handout Practice

✓ A. Fill in the Blanks — Answers

1 A sequence is an ordered list of numbers. Each number in a sequence is called a term.
2 In an AP, we add the same number called the common difference (d).
3 The nth term of an AP is t(n) = a + (n − 1) × d. Here a is the first term and d is the common difference.
4 In a GP, we multiply by the same number called the common ratio (r).
5 Sum of 1 to n = n × (n + 1) ÷ 2. Formula: S = n(n + 1) ÷ 2.
🏆 Answers: (1) numbers   (2) common difference   (3) a, d   (4) common ratio   (5) 2

✓ B. True or False — Answers

1 "2, 5, 8, 11, 14 is an AP with d = 3." ➡ TRUE. Check: 5 − 2 = 3, 8 − 5 = 3, 11 − 8 = 3, 14 − 11 = 3. The difference is the same every time, so it is an AP.
2 "1, 3, 9, 27 is an AP." ➡ FALSE. Check: 3 − 1 = 2, 9 − 3 = 6. The differences are not equal. This is a GP (each term is multiplied by 3), not an AP.
3 "In a GP, you add the same number each time." ➡ FALSE. In a GP, you multiply by the same number (the common ratio r). Adding is what happens in an AP.
4 "The sum of 1 to 10 is 55." ➡ TRUE. Using the formula S = n(n+1)/2: S = 10 × 11 ÷ 2 = 110 ÷ 2 = 55. ✓
🏆 Answers: (1) True   (2) False   (3) False   (4) True

✓ C. Problem 1: AP with a = 7, d = 3. Find the 10th term.

1 Write down the formula: t(n) = a + (n − 1) × d.
2 Identify values: a = 7 (first term), d = 3 (common difference), n = 10.
3 Substitute: t(10) = 7 + (10 − 1) × 3.
4 Simplify inside brackets: 10 − 1 = 9.
5 Multiply: 9 × 3 = 27.
6 Add: 7 + 27 = 34.
🏆 Answer: The 10th term = 34.

💡 Quick check: The sequence is 7, 10, 13, 16, 19, 22, 25, 28, 31, 34. Count to the 10th term to confirm!

✓ C. Problem 2: Find the sum of 1 + 2 + 3 + ... + 20.

1 Formula for sum of 1 to n: S = n × (n + 1) ÷ 2.
2 Identify: n = 20 (last number).
3 Substitute: S = 20 × (20 + 1) ÷ 2.
4 Simplify: S = 20 × 21 ÷ 2.
5 Multiply: 20 × 21 = 420.
6 Divide: 420 ÷ 2 = 210.
🏆 Answer: 1 + 2 + 3 + ... + 20 = 210.

💡 Why does this work? Pair up: 1+20=21, 2+19=21, 3+18=21, ... There are 10 such pairs. 10 × 21 = 210.

✓ D. Match the Columns — Answers

1 AP ⟶ (b) Add same number. An arithmetic progression adds a fixed common difference d each time.
2 GP ⟶ (a) Multiply by same number. A geometric progression multiplies by a fixed common ratio r each time.
3 Common difference ⟶ (d) The fixed amount added. In an AP, d = t(n) − t(n−1).
4 Sum of 1 to n ⟶ (c) n(n+1)/2. This is the formula discovered by Gauss.
🏆 Answers: 1→(b), 2→(a), 3→(d), 4→(c)

✓ E. Write the Next 3 Terms

1 AP: 4, 9, 14, __, __, __
Common difference d = 9 − 4 = 5. Add 5 each time.
Next terms: 14 + 5 = 19, 19 + 5 = 24, 24 + 5 = 29.
2 GP: 5, 10, 20, __, __, __
Common ratio r = 10 ÷ 5 = 2. Multiply by 2 each time.
Next terms: 20 × 2 = 40, 40 × 2 = 80, 80 × 2 = 160.
🏆 Answers: (1) 19, 24, 29    (2) 40, 80, 160

🃏 Section 6 — Revision Flashcards

Front
What is a sequence?
Back

An ordered list of numbers. Each number is a term.

Front
What is an explicit rule?
Back

A formula using n to find any term directly. Example: t(n) = 4n + 1.

Front
What is an AP?
Back

A sequence that adds the same number (d) each time. Example: 5, 8, 11, 14.

Front
nth term of AP formula?
Back

t(n) = a + (n − 1) × d. a = first term, d = common difference.

Front
Sum of 1 + 2 + ... + n?
Back

S = n × (n + 1) ÷ 2. Example: 1 to 10 = 55.

Front
What is a GP?
Back

A sequence that multiplies by the same number (r) each time. Example: 4, 12, 36.

Front
nth term of GP formula?
Back

t(n) = a × r(n−1). a = first term, r = common ratio.

Front
AP vs GP: what is the difference?
Back

AP adds d each time. GP multiplies by r each time. GP grows much faster!

🧠 Section 7 — Mind Map

SEQUENCES & PROGRESSIONS What is a Sequence? Ordered list of numbers Finite or infinite Patterns and Rules Explicit: use n directly Recursive: use previous term Arithmetic (AP) Add d each time t(n) = a + (n−1)d Common Difference d = t(n) − t(n−1) Same gap every time Geometric (GP) Multiply by r each time t(n) = a × r(n−1) Sum of 1 to n S = n(n+1) ÷ 2 Pair up from both ends Common Ratio r = t(n) ÷ t(n−1) Same multiplier every time AP vs GP AP: grows steady (linear) GP: grows fast (exponential)

All the key ideas about sequences and progressions in one picture.