🔊 Class 9 Science – Sound Waves
Original Visual Revision Notes Aligned with the Class 9 Science syllabus. Independently created study material. Not affiliated with or endorsed by NCERT.

📑 What is inside this lesson

📝 Section 1 — Classroom Notes

💡 Think about this first! Drop a stone into still water and watch the ripples spread outward in circles. Sound works in a very similar way — except it travels through the air as invisible push-and-pull waves instead of water ripples. Every time something vibrates (a drum skin, a guitar string, your own vocal cords) it pushes the air particles around it. Those particles push their neighbors, and so on — carrying the sound all the way to your ears. In this lesson, we explore how these invisible waves work, travel, and bring us all the sounds we hear.

🥁 Topic 1: How Sound is Made

🌊 Topic 2: Sound Needs a Medium

🔘 Topic 3: Sound Waves — Compressions and Rarefactions

📏 Topic 4: Wavelength, Frequency, and Time Period

🚀 Topic 5: Speed of Sound

📣 Topic 6: Amplitude and Loudness

🎵 Topic 7: Pitch and Frequency

👂 Topic 8: Audible, Infrasonic, and Ultrasonic

🏔 Topic 9: Echo and Reflection of Sound

🦇 Topic 10: SONAR and Echolocation

🎨 Section 2 — Easy Illustrations

Sound Wave: Compressions and Rarefactions C R C R Dark = Compression (particles close together) Light = Rarefaction (particles spread apart) Source

Fig 1: Compressions and rarefactions moving through a tube

Wavelength and Amplitude λ (wavelength) Amplitude Crest Trough

Fig 2: Wavelength and amplitude marked on a wave

Speed of Sound in Different Media Solid Liquid Gas 5000 m/s 1500 m/s 340 m/s Sound travels fastest in solids, slowest in gases

Fig 3: Comparing speed of sound in solid, liquid, and gas

Wall sound wave echo echo delay ≥ 0.1 s

Fig 4: An echo needs a minimum distance to a wall

How SONAR Finds Underwater Objects Transmitter Receiver pulse sent pulse received Underwater Object

Fig 5: SONAR uses ultrasonic waves to find underwater objects

🔬 Section 3 — Worked Examples

💡 Example 1: Speed of Sound

A sound wave has frequency 250 Hz and wavelength 1.36 m. Find its speed.

1
Speed = frequency × wavelength.
2
Speed = 250 × 1.36.
3
Speed = 340 m/s.
v = ν × λ
Answer: The speed of sound is 340 m/s.

💡 Example 2: Echo Distance

You clap and hear the echo after 0.4 s. Speed of sound is 340 m/s. Find the distance to the wall.

1
Total distance travelled = speed × time.
2
Total distance = 340 × 0.4 = 136 m.
3
Sound travels to wall and back, so divide by 2.
Distance = (Speed × Time) ÷ 2
Answer: The wall is 68 m away.

💡 Example 3: SONAR Depth

A ship sends an ultrasonic signal. It returns after 1.2 s. Speed of sound in seawater is 1500 m/s. Find the depth.

1
Total distance travelled = speed × time.
2
Total distance = 1500 × 1.2 = 1800 m.
3
Signal goes down and comes back, so divide by 2.
Depth = (Speed × Time) ÷ 2
Answer: The depth of the seabed is 900 m.

📋 Section 4 — Cheat Sheet

TermMeaning
VibrationQuick to-and-fro motion of an object.
MediumMaterial through which sound travels.
Longitudinal WaveParticles vibrate along the wave direction.
CompressionRegion where particles are packed close together.
RarefactionRegion where particles are spread far apart.
Wavelength (λ)Distance between two nearby compressions or rarefactions.
Frequency (ν)Number of oscillations completed every second.
Time Period (T)Time taken for one complete oscillation.
AmplitudeMaximum change in density from the average.
Speed of SoundDistance sound covers in one second.
PitchHow high or low a sound feels.
LoudnessHow soft or loud a sound feels.
Audible RangeSound humans can hear, 20 Hz to 20000 Hz.
SONARSystem using ultrasound to find underwater objects.

🏠 Section 5 — Take-Home Handout

Part A: Fill in the Blanks

Part B: True or False

Part C: Solve These

1. A wave has frequency 200 Hz and wavelength 1.7 m. Find its speed.

2. A ship hears its echo after 2 s in water where speed is 1500 m/s. Find the depth.

3. A sound of frequency 50 Hz repeats how many times in 4 seconds?

Part D: Match the Columns

Column AColumn BYour Answer
1. WavelengthA. Number of oscillations per second
2. FrequencyB. Distance between two compressions
3. AmplitudeC. Sound reflected back to our ears
4. EchoD. Decides how loud a sound is
5. SONARE. Finds objects underwater using sound

Part E: Draw and Label

Draw a sound wave in a tube. Label the compression and rarefaction regions.

✅ Detailed Solutions — Section 5 Take-Home Handout

Part A: Fill in the Blanks — Answers

  1. Sound is produced by a vibrating object.
  2. Sound cannot travel through a vacuum.
  3. Compressions are regions of high density.
  4. The unit of frequency is hertz (Hz).
  5. High frequency sound has a high pitch.

Part B: True or False — Answers

  1. False. Sound cannot travel through vacuum because there are no particles to vibrate and pass the sound energy forward.
  2. True. Larger amplitude means the particles compress and expand more, creating a louder sound.
  3. False. Ultrasonic sound has frequency above 20,000 Hz. Below 20 Hz is called infrasonic.
  4. True. SONAR sends ultrasonic pulses from a ship and measures how long it takes for the echo to return.
  5. True. Our ears retain sound for 0.1 s, so the echo must arrive at least 0.1 s after the original sound to be heard separately.

Part C: Solve These — Step-by-Step Solutions

Q1. A wave has frequency 200 Hz and wavelength 1.7 m. Find its speed.

1
Speed = frequency × wavelength.
2
Speed = 200 × 1.7 = 340 m/s.
Answer: Speed of sound = 340 m/s.

Q2. A ship hears its echo after 2 s in water where speed is 1500 m/s. Find the depth.

1
Total distance = speed × time = 1500 × 2 = 3000 m.
2
Sound travels to the seabed and comes back, so divide by 2.
3
Depth = 3000 ÷ 2 = 1500 m.
Answer: The depth of the seabed is 1500 m.

Q3. A sound of frequency 50 Hz repeats how many times in 4 seconds?

1
Frequency = 50 Hz means 50 oscillations every second.
2
In 4 seconds: 50 × 4 = 200 oscillations.
Answer: The sound completes 200 oscillations (cycles) in 4 seconds.

Part D: Match the Columns — Answers

Column AMatchColumn B
1. Wavelength→ BDistance between two compressions
2. Frequency→ ANumber of oscillations per second
3. Amplitude→ DDecides how loud a sound is
4. Echo→ CSound reflected back to our ears
5. SONAR→ EFinds objects underwater using sound

🔄 Section 6 — Revision Flashcards

Light side = Question. Dark side = Answer.

What makes sound?
Vibrating objects make sound.
Can sound travel through vacuum?
No, sound needs a medium.
What is a compression?
A region of tightly packed particles.
What is the unit of frequency?
Hertz, written as Hz.
What decides the pitch of sound?
Frequency decides the pitch.
What decides the loudness of sound?
Amplitude decides the loudness.
What is the audible range for humans?
20 Hz to 20000 Hz.
What does SONAR stand for?
Sound Navigation And Ranging.

🧠 Section 7 — Mind Map

Sound Waves Production Vibrating objects Tuning fork strings Medium Needed Solid liquid gas No sound in vacuum Wave Type Longitudinal wave Compressions rarefactions Wave Properties Wavelength frequency v = λ × ν Loudness & Pitch Amplitude = loudness Frequency = pitch Hearing Range 20 Hz to 20000 Hz Infra and ultrasonic Echo & Reflection Far reflecting surface Time gap 0.1 s SONAR Ultrasound underwater Find depth and objects

Fig 6: Mind map of sound waves and their properties

⚠ This is independently created study material aligned with the Class 9 Science syllabus. Not affiliated with or endorsed by NCERT or any government body.