🚗 Class 9 Science – Describing Motion Around Us
Original Visual Revision Notes Aligned with the Class 9 Science syllabus. Independently created study material. Not affiliated with or endorsed by NCERT.

📖 What is Inside

📝 Section 1 — Classroom Notes

Have you ever noticed that when you are sitting in a moving train, the trees seem to fly past you — but the person sitting next to you seems perfectly still? This is because motion is relative. Whether something is "moving" or "at rest" depends entirely on what you compare it to. This simple idea is the foundation of everything we study in this chapter.

Scientists describe motion using numbers — distance, speed, velocity, and acceleration. Just like a cricket commentator describes a ball's speed in km/h, scientists use precise measurements and equations to describe exactly how fast, how far, and in which direction an object is moving. These numbers let us predict where a rocket will land, how long a journey takes, and why a car needs a safe braking distance.

In this chapter, we will learn the three famous equations of motion, understand position-time and velocity-time graphs, and explore what happens when objects move in circles. By the end, you will be able to calculate the speed of a running cheetah, the acceleration of a sports car, and the distance covered by a falling stone — all with simple maths!

🚶 Topic 1: What is Motion?

📏 Topic 2: Reference Point and Position

👣 Topic 3: Distance and Displacement

⏰ Topic 4: Average Speed

🎯 Topic 5: Average Velocity

🚀 Topic 6: Acceleration

📐 Topic 7: Equations of Motion

📈 Topic 8: Position-Time Graphs

📊 Topic 9: Velocity-Time Graphs

🔄 Topic 10: Uniform Circular Motion

🎨 Section 2 — Easy Illustrations

Distance vs Displacement Start (A) End (B) Curved path = Distance (total path walked) Straight line = Displacement (shortest path, start to end) Distance ≥ Displacement (always!)

Fig 1: Distance is the full path. Displacement is the straight line from start to end.

Position-Time Graph (Constant Speed) Time (s) Position (m) 0 1 2 3 4 5 0 10 20 30 40 50 2 s 20 m Slope = 20/2 = 10 m/s Straight line = constant speed

Fig 2: A straight line on a position-time graph means constant speed. The slope gives velocity.

Velocity-Time Graph (Constant Acceleration) Time (s) Velocity (m/s) 0 2 4 6 8 10 0 4 8 12 16 20 Shaded area = Displacement Slope = acceleration = 2 m/s²

Fig 3: The slope of a velocity-time graph gives acceleration. The shaded area gives displacement.

Three Equations of Motion Equation 1 v = u + at Finds: final velocity Uses: u, a, t Equation 2 s = ut + ½at² Finds: displacement Uses: u, a, t Equation 3 v² = u² + 2as Finds: velocity (no time) Uses: u, a, s What the Letters Mean u = start velocity v = end velocity a = acceleration s = displacement t = time taken These equations work ONLY for constant acceleration.

Fig 4: The three kinematic equations and what each letter stands for.

Uniform Circular Motion Centre R v v v v Speed = same (v) always constant Direction = changes always turning Velocity = changes (direction is changing) One full round: distance = 2πR displacement = 0

Fig 5: In uniform circular motion, speed stays the same but direction keeps changing, so velocity changes.

✏️ Section 3 — Worked Examples

💡 Example 1: Finding Average Speed and Average Velocity

A boy walks 80 m east, then turns and walks 30 m west. He takes 55 s in total. Find his average speed and average velocity.

1
Write what we know.
Total distance = 80 m + 30 m = 110 m.
Displacement = 80 m − 30 m = 50 m east.
Time = 55 s.
2
Find average speed.
Average speed = total distance ÷ time
= 110 m ÷ 55 s = 2 m/s.
3
Find average velocity.
Average velocity = displacement ÷ time
= 50 m ÷ 55 s ≈ 0.91 m/s east.
✔ Average speed = 2 m/s. Average velocity ≈ 0.91 m/s east.

💡 Example 2: Using Equations of Motion

A scooter starts from rest and speeds up at 3 m/s² for 8 seconds. Find the final velocity and the distance covered.

1
Write what we know.
u = 0 m/s (starts from rest), a = 3 m/s², t = 8 s.
2
Find final velocity using Equation 1.
v = u + at
v = 0 + 3 × 8 = 24 m/s.
3
Find distance using Equation 2.
s = ut + ½at²
s = 0 × 8 + ½ × 3 × 8²
s = 0 + ½ × 3 × 64 = 96 m.
✔ Final velocity = 24 m/s. Distance covered = 96 m.

💡 Example 3: Braking Distance

A car moves at 72 km/h and brakes are applied. The acceleration is −5 m/s². How far does it go before stopping?

1
Convert speed to m/s.
72 km/h = 72 × 1000 ÷ 3600 = 20 m/s.
2
Write what we know.
u = 20 m/s, v = 0 m/s (stops), a = −5 m/s².
3
Use Equation 3 to find distance.
v² = u² + 2as
0 = (20)² + 2 × (−5) × s
0 = 400 − 10s
10s = 400
s = 40 m.
✔ The car travels 40 m before stopping.

📋 Section 4 — Cheat Sheet

TermMeaningUnit / Note
MotionChange in position over time—
RestPosition does not change—
Reference pointFixed point to measure fromAlso called origin
DistanceTotal path lengthm (always positive)
DisplacementShortest path from start to endm (has direction)
Average speedDistance ÷ timem/s (no direction)
Average velocityDisplacement ÷ timem/s (has direction)
AccelerationChange in velocity ÷ timem/s²
Uniform motionEqual distances in equal timesSpeed is constant
Position-time graphShows position vs timeSlope = velocity
Velocity-time graphShows velocity vs timeSlope = acceleration, Area = displacement
Equation 1v = u + atFinds final velocity
Equation 2s = ut + ½at²Finds displacement
Equation 3v² = u² + 2asNo time needed
Uniform circular motionSame speed in a circleDirection always changes
💭 Remember: Speed has no direction. Velocity has direction. Acceleration tells how fast velocity changes.

🏠 Section 5 — Take-Home Handout

✏️ Part A: Fill in the Blanks

✅ Part B: True or False

🔢 Part C: Solve These

C1. A cyclist goes 150 m in 30 s. What is the average speed?

C2. A bus starts from rest and reaches 18 m/s in 6 s. What is the acceleration?

C3. A van moves at 90 km/h. Convert this speed to m/s.

🔗 Part D: Match the Columns

Column AColumn B
1. Distancea. Displacement ÷ time
2. Average velocityb. Total path length
3. Accelerationc. v = u + at
4. Equation 1d. Change in velocity ÷ time
5. Uniform circular motione. Same speed, changing direction

Answers: 1–____, 2–____, 3–____, 4–____, 5–____

🎨 Part E: Draw and Label

Draw a velocity-time graph for a car that:

Label the axes (time, velocity) and mark the points.

✅ Detailed Solutions — Section 5 Take-Home Handout

Part A — Fill in the Blanks (Answers)

  1. The change in position of a thing is called motion.
  2. Distance is always zero or positive — it can never be negative because it is total path length.
  3. Displacement can be positive, negative, or zero. (Zero when you return to your starting point.)
  4. Average speed = total distance ÷ total time.
  5. The SI unit of acceleration is m/s² (metres per second squared).
  6. In uniform motion, an object covers equal distances in equal times.
  7. On a position-time graph, the slope gives the velocity (speed with direction).
  8. On a velocity-time graph, the area under the line gives displacement.
  9. The first equation of motion is v = u + at.
  10. In uniform circular motion, speed is constant but direction keeps changing.

Part B — True or False (Answers)

  1. False. Distance can never be negative. It is total path length, always zero or positive.
  2. True. Walk in a circle and return to start: displacement = 0, distance = full circle length.
  3. False. Speed and velocity are NOT always the same. Speed has no direction; velocity has direction.
  4. True. Negative acceleration (deceleration) means velocity is decreasing — the object is slowing down.
  5. False. A flat horizontal line means position is NOT changing — the object is at rest.

Part C — Solve (Step-by-Step)

C1. Cyclist goes 150 m in 30 s. Average speed?

1Formula: Speed = Distance ÷ Time
2= 150 ÷ 30 = 5
✔ Average speed = 5 m/s

C2. Bus starts from rest, reaches 18 m/s in 6 s. Acceleration?

1Formula: a = (v − u) ÷ t
2a = (18 − 0) ÷ 6 = 18 ÷ 6 = 3
✔ Acceleration = 3 m/s²

C3. Van moves at 90 km/h. Convert to m/s.

1Rule: divide km/h by 3.6 to get m/s
2= 90 ÷ 3.6 = 25
✔ Speed = 25 m/s

Part D — Match the Columns (Answers)

  1. Distance → b. Total path length
  2. Average velocity → a. Displacement ÷ time
  3. Acceleration → d. Change in velocity ÷ time
  4. Equation 1 → c. v = u + at
  5. Uniform circular motion → e. Same speed, changing direction

Part E — Velocity-Time Graph (Guidance)

🃏 Section 6 — Revision Flashcards

Light side = Question. Dark side = Answer.

Q1: What is motion?
A1: Change in position of a thing over time.
Q2: What is the difference between distance and displacement?
A2: Distance = total path. Displacement = shortest path from start to end with direction.
Q3: What is average speed?
A3: Total distance divided by total time. No direction. Unit: m/s.
Q4: What is acceleration?
A4: Change in velocity divided by time. Unit: m/s².
Q5: Write the three equations of motion.
A5: v = u + at, s = ut + ½at², v² = u² + 2as.
Q6: What does the slope of a position-time graph tell us?
A6: It tells us the velocity (speed with direction).
Q7: What does the area under a velocity-time graph tell us?
A7: It tells us the displacement (distance in one direction).
Q8: What is uniform circular motion?
A8: Moving in a circle at constant speed. Speed stays the same but direction keeps changing.

🧠 Section 7 — Mind Map

Describing Motion Motion & Rest Need reference point • Position changes = motion • Position fixed = rest Distance vs Displacement • Distance = total path • Displacement = shortest Average Speed = distance ÷ time • No direction, always + Average Velocity = displacement ÷ time • Has direction (+/−) Acceleration = Δv ÷ Δt • + ve = speeding up • − ve = slowing down Equations of Motion (constant acceleration) • v = u + at • s = ut + ½at² • v² = u² + 2as Graphs Position & Velocity • Slope & area give info Circular Motion Speed same, dir. changes • distance = 2πR per round

Mind Map: Describing Motion Around Us — 8 key ideas at a glance.